你这个+CIPSNTPTIME返回的时间字符串格式本质上就是ctime()风格（例如：Wed Feb 4 10:14:03 2026），其中：
周：固定是 3 字母英文缩写
月：固定是 3 字母英文缩写
下面把“周 / 月”的枚举（以及字符串表）给你整理好，顺便附一个最常用的解析/映射写法。
周（Weekday）枚举 & 字符串
周的缩写一共 7 个（从周日开始）：
Sun, Mon, Tue, Wed, Thu, Fri, Sat
常见做法（对齐struct tm.tm_wday习惯：0=Sun）：
typedef enum { WEEK_SUN = 0, WEEK_MON, WEEK_TUE, WEEK_WED, WEEK_THU, WEEK_FRI, WEEK_SAT, WEEK_INVALID = 0xFF } weekday_t; static const char* const WEEK_STR[7] = { "Sun", "Mon", "Tue", "Wed", "Thu", "Fri", "Sat" };月（Month）枚举 & 字符串
月的缩写一共 12 个：
Jan, Feb, Mar, Apr, May, Jun, Jul, Aug, Sep, Oct, Nov, Dec
常见做法（对齐struct tm.tm_mon习惯：0=Jan）：
typedef enum { MON_JAN = 0, MON_FEB, MON_MAR, MON_APR, MON_MAY, MON_JUN, MON_JUL, MON_AUG, MON_SEP, MON_OCT, MON_NOV, MON_DEC, MON_INVALID = 0xFF } month_t; static const char* const MONTH_STR[12] = { "Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec" };字符串 → 枚举/数字 映射函数（推荐直接用）
#include <string.h> #include <stdint.h> static weekday_t weekday_from_str(const char *w) { for (int i = 0; i < 7; i++) { if (strcmp(w, WEEK_STR[i]) == 0) return (weekday_t)i; } return WEEK_INVALID; } static month_t month_from_str(const char *m) { for (int i = 0; i < 12; i++) { if (strcmp(m, MONTH_STR[i]) == 0) return (month_t)i; } return MON_INVALID; }从Wed Feb 4 10:14:03 2026解析出周/月（示例）
注意日期前可能有双空格（Feb␠␠4），%d能正确处理：
#include <stdio.h> typedef struct { weekday_t wday; // 0..6, Sun..Sat month_t mon; // 0..11, Jan..Dec int day; // 1..31 int hour, min, sec; int year; // e.g. 2026 } ntp_time_t; int parse_cipsntptime(const char *s, ntp_time_t *out) { char w[4] = {0}, m[4] = {0}; int day, hh, mm, ss, yy; // 只解析形如: "Wed Feb 4 10:14:03 2026" if (sscanf(s, "%3s %3s %d %d:%d:%d %d", w, m, &day, &hh, &mm, &ss, &yy) != 7) { return -1; } out->wday = weekday_from_str(w); out->mon = month_from_str(m); out->day = day; out->hour = hh; out->min = mm; out->sec = ss; out->year = yy; if (out->wday == WEEK_INVALID || out->mon == MON_INVALID) return -2; return 0; }
