[免费]基于Python的Flask+Vue物业管理系统【论文+源码+SQL脚本】-平芜编程栈

大家好，我是java1234_小锋老师，看到一个不错的基于Python的Flask+Vue物业管理系统【论文+源码+SQL脚本】，分享下哈。

项目视频演示

https://www.bilibili.com/video/BV1AEqpBFExf/

项目介绍

本文首先实现了基于Python的Flask+Vue物业管理系统技术的发展随后依照传统的软件开发流程，最先为系统挑选适用的言语和软件开发平台，依据需求分析开展控制模块制做和数据库查询构造设计，随后依据系统整体功能模块的设计，制作系统的功能模块图、E-R图。随后，设计框架，依据设计的框架撰写编码，完成系统的每个功能模块。最终，对基本系统开展了检测，包含软件性能测试、单元测试和性能指标。测试结果表明，该系统能够实现所需的功能，运行状况尚可并无明显缺点。

系统展示

部分代码

import logging from flask import Blueprint, request from extensions import db from util.make_menu_tree import build_menu_tree from menu.model import SysMenu from util.security import permission_required from util.status_code import response, SUCCESS_CODE, ERROR_CODE menu_print = Blueprint('menu_print',__name__,url_prefix='/api/menu') logging.basicConfig(level=logging.INFO, format='%(asctime)s - %(levelname)s - %(message)s') def to_list_(menu): dict_users = { "menu_id": menu.get("menuId"), "parent_id": menu.get("parentId"), "menu_label": menu.get("menuLabel"), "menu_code": menu.get("menuCode"), "name": menu.get("name"), "path": menu.get("path"), "url": menu.get("url"), "type": menu.get("type"), "icon": menu.get("icon"), "order_num": menu.get("orderNum"), "remark": menu.get("remark"), "parent_name": menu.get("parentName") } return dict_users @menu_print.route('/list',methods=['GET']) @permission_required('sys:sysMenuList') def get_menu_list(): """ 查询所有菜单，并构造树形结构返回 """ menu_list = SysMenu.query.order_by(SysMenu.menu_id).all() menu_list=[x.to_list() for x in menu_list] res_menu_list = build_menu_tree(menu_list) return response("成功", SUCCESS_CODE, data=res_menu_list) @menu_print.route('',methods=['PUT']) @permission_required('sys:menu:edit') def update_menu(): """ 修改菜单 """ new_menu = request.get_json() try: old_menu=SysMenu.query.filter_by(menu_id=new_menu['menuId']).first() if old_menu: # 更新这条 SysMenu.query.filter_by(menu_id=new_menu['menuId']).update(to_list_(new_menu)) db.session.commit() else: return response("菜单不存在", ERROR_CODE) except: db.session.rollback() return response("修改失败", ERROR_CODE) return response("修改成功", SUCCESS_CODE) @menu_print.route('<int:menu_id>',methods=['DELETE']) @permission_required('sys:menu:delete') def delete_menu(menu_id): """ 删除菜单 """ try: menu = SysMenu.query.filter_by(menu_id=menu_id).first() if menu: SysMenu.query.filter_by(menu_id=menu_id).delete() SysMenu.query.filter_by(parent_id=menu_id).delete() db.session.commit() else: return response("菜单不存在", ERROR_CODE) except: db.session.rollback() return response("删除失败", ERROR_CODE) return response("删除成功", SUCCESS_CODE) def make_menu_tree( menus, parent_id): """ 递归构造树形菜单 """ result = [] for menu in menus: if menu['parentId'] == parent_id: children = make_menu_tree(menus, menu['menuId']) if children: menu['children'] = children result.append(menu) return result @menu_print.route('/parent',methods=['GET']) @permission_required('sys:sysMenuList') def get_parent_list(): """ 查询上级菜单，并构造树形结构返回 """ # 查询符合条件的菜单，并按 order_num 升序排序 menus = SysMenu.query.order_by(SysMenu.order_num.asc()).all() menus = [menu.to_list() for menu in menus] # 添加顶级菜单节点 top_menu = { "menuId": 0, "parentId": -1, "menuLabel":"顶级菜单" } menus.append(top_menu) # 构造树形数据 menu_tree = make_menu_tree(menus, -1) return response("成功", SUCCESS_CODE, data=menu_tree) @menu_print.route('',methods=['POST']) @permission_required('sys:menu:add') def add_menu(): """ 添加菜单 """ mjson = request.get_json() new_menu = SysMenu( parent_id=mjson['parentId'], menu_label=mjson['menuLabel'], menu_code=mjson['menuCode'], name=mjson['name'], path=mjson['path'], url=mjson['url'], type=mjson['type'], icon=mjson['icon'], remark=mjson['remark'], parent_name=mjson['parentName'], ) try: db.session.add(new_menu) db.session.commit() return response("添加成功", SUCCESS_CODE, data=new_menu.to_list()) except Exception as e: print(e) db.session.rollback() return response("添加失败", ERROR_CODE)